I can't find the answer I want for a particular question (java)

Issue

import java.util.Scanner;

public class SumAverage2 {

    public static void main(String[] args) {
        Scanner input = new Scanner(System.in);
        System.out.println("average program");
        System.out.println("Enter multiple integers greater than or equal to 0.");
        System.out.println("Enter a negative integer to finish the entry.");
        
        boolean end = false;
        int n;
        int sum = 0;
        int count = 0;
        
        while(!end) {
            n = input.nextInt();
            if (n>=0) {
                sum = sum + n;
                count++;
            }else
                end = true;
        }
        
        double average ;
        average = (double) sum / (double) count ;
        System.out.println("Number of integers greater than 0 entered  = " + count);
        System.out.println("sum of integers = " + sum);
        System.out.printf("average = %.2f", + average);
        
        input.close();
    }

}

I'm trying to solve this problem, but the answer I want doesn't come out under certain conditions.

If I enter

3 7 1 -1

average program

Enter multiple integers greater than or equal to 0.

Enter a negative integer to finish the entry.

Number of integers greater than 0 entered = 3

sum of integers = 11

average = 3.67

// I made a program that comes out with this answer.

However, the condition "Do not output the sum and average if the user inputs a negative integer from the beginning" must be satisfied, but the code above does not work.

If I enter -10

average program

Enter multiple integers greater than or equal to 0.

Enter a negative integer to finish the entry.

Number of integers greater than 0 entered = 0

sum of integers = 0 average = NaN

// The answer comes as above.

The answer i want is //

average program

Enter multiple integers greater than or equal to 0.

Enter a negative integer to finish the entry.

Number of integers greater than 0 entered = 0 //

I've only been learning to code for 2 weeks, so I'm having a lot of difficulties. I'd be very grateful if you guys could help me.

Wrong answer press -10 //

average program

Enter multiple integers greater than or equal to 0.

Enter a negative integer to finish the entry.

Number of integers greater than 0 entered = 0

sum of integers = 0

average = NaN

Correct answer press -10 //

average program

Enter multiple integers greater than or equal to 0.

Enter a negative integer to finish the entry.

Number of integers greater than 0 entered = 0

I want to solve a problem that does not work under certain conditions.

Solution

Your count is the number of numbers entered.

Wrap all the 'printing sum and average' stuff in 'if count > 0'.

System.out.println("Number of integers greater than 0 entered  = " + count);
if (count > 0) {
    double average = (double) sum / (double) count;
    System.out.println("sum of integers = " + sum);
    System.out.printf("average = %.2f", + average);
}

Answered By - Arfur Narf